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3(4-x)-(2x+3)=5+3(x-4)
We move all terms to the left:
3(4-x)-(2x+3)-(5+3(x-4))=0
We add all the numbers together, and all the variables
3(-1x+4)-(2x+3)-(5+3(x-4))=0
We multiply parentheses
-3x-(2x+3)-(5+3(x-4))+12=0
We get rid of parentheses
-3x-2x-(5+3(x-4))-3+12=0
We calculate terms in parentheses: -(5+3(x-4)), so:We add all the numbers together, and all the variables
5+3(x-4)
determiningTheFunctionDomain 3(x-4)+5
We multiply parentheses
3x-12+5
We add all the numbers together, and all the variables
3x-7
Back to the equation:
-(3x-7)
-5x-(3x-7)+9=0
We get rid of parentheses
-5x-3x+7+9=0
We add all the numbers together, and all the variables
-8x+16=0
We move all terms containing x to the left, all other terms to the right
-8x=-16
x=-16/-8
x=+2
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