3(4-x)=10-2(3x+1)

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Solution for 3(4-x)=10-2(3x+1) equation: 



3(4-x)=10-2(3x+1)

We move all terms to the left:

3(4-x)-(10-2(3x+1))=0

We add all the numbers together, and all the variables

3(-1x+4)-(10-2(3x+1))=0

We multiply parentheses

-3x-(10-2(3x+1))+12=0



We calculate terms in parentheses: -(10-2(3x+1)), so:

10-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+10

We multiply parentheses

-6x-2+10

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We get rid of parentheses

-3x+6x-8+12=0

We add all the numbers together, and all the variables

3x+4=0

We move all terms containing x to the left, all other terms to the right

3x=-4

x=-4/3

x=-1+1/3

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