3(4-x)=21x-3+4

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Solution for 3(4-x)=21x-3+4 equation: 



3(4-x)=21x-3+4

We move all terms to the left:

3(4-x)-(21x-3+4)=0

We add all the numbers together, and all the variables

3(-1x+4)-(21x+1)=0

We multiply parentheses

-3x-(21x+1)+12=0

We get rid of parentheses

-3x-21x-1+12=0

We add all the numbers together, and all the variables

-24x+11=0

We move all terms containing x to the left, all other terms to the right

-24x=-11

x=-11/-24

x=11/24

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