3(4/5z-2)=12

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Solution for 3(4/5z-2)=12 equation: 



3(4/5z-2)=12

We move all terms to the left:

3(4/5z-2)-(12)=0



Domain of the equation: 5z-2)!=0

z∈R



We multiply parentheses

12z-6-12=0

We add all the numbers together, and all the variables

12z-18=0

We move all terms containing z to the left, all other terms to the right

12z=18

z=18/12

z=1+1/2

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