3(42+6)=4(2z+5)

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Solution for 3(42+6)=4(2z+5) equation: 



3(42+6)=4(2z+5)

We move all terms to the left:

3(42+6)-(4(2z+5))=0

We add all the numbers together, and all the variables

-(4(2z+5))+348=0



We calculate terms in parentheses: -(4(2z+5)), so:

4(2z+5)

We multiply parentheses

8z+20

Back to the equation:

-(8z+20)



We get rid of parentheses

-8z-20+348=0

We add all the numbers together, and all the variables

-8z+328=0

We move all terms containing z to the left, all other terms to the right

-8z=-328

z=-328/-8

z=+41

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