3(42-4p)=7p+3(8p-4)

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Solution for 3(42-4p)=7p+3(8p-4) equation: 



3(42-4p)=7p+3(8p-4)

We move all terms to the left:

3(42-4p)-(7p+3(8p-4))=0

We add all the numbers together, and all the variables

3(-4p+42)-(7p+3(8p-4))=0

We multiply parentheses

-12p-(7p+3(8p-4))+126=0



We calculate terms in parentheses: -(7p+3(8p-4)), so:

7p+3(8p-4)

We multiply parentheses

7p+24p-12

We add all the numbers together, and all the variables

31p-12

Back to the equation:

-(31p-12)



We get rid of parentheses

-12p-31p+12+126=0

We add all the numbers together, and all the variables

-43p+138=0

We move all terms containing p to the left, all other terms to the right

-43p=-138

p=-138/-43

p=3+9/43

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