3(48+4z)=24z

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Solution for 3(48+4z)=24z equation: 



3(48+4z)=24z

We move all terms to the left:

3(48+4z)-(24z)=0

We add all the numbers together, and all the variables

3(4z+48)-24z=0

We add all the numbers together, and all the variables

-24z+3(4z+48)=0

We multiply parentheses

-24z+12z+144=0

We add all the numbers together, and all the variables

-12z+144=0

We move all terms containing z to the left, all other terms to the right

-12z=-144

z=-144/-12

z=+12

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