3(4K+4)-5=10k-3(k-4)

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Solution for 3(4K+4)-5=10k-3(k-4) equation: 



3(4+4)-5=10K-3(K-4)

We move all terms to the left:

3(4+4)-5-(10K-3(K-4))=0

We add all the numbers together, and all the variables

-(10K-3(K-4))-5+38=0

We add all the numbers together, and all the variables

-(10K-3(K-4))+33=0



We calculate terms in parentheses: -(10K-3(K-4)), so:

10K-3(K-4)

We multiply parentheses

10K-3K+12

We add all the numbers together, and all the variables

7K+12

Back to the equation:

-(7K+12)



We get rid of parentheses

-7K-12+33=0

We add all the numbers together, and all the variables

-7K+21=0

We move all terms containing K to the left, all other terms to the right

-7K=-21

K=-21/-7

K=+3

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