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3(4a+2)=2(a+-2)
We move all terms to the left:
3(4a+2)-(2(a+-2))=0
We add all the numbers together, and all the variables
3(4a+2)-(2(a-2))=0
We multiply parentheses
12a-(2(a-2))+6=0
We calculate terms in parentheses: -(2(a-2)), so:We get rid of parentheses
2(a-2)
We multiply parentheses
2a-4
Back to the equation:
-(2a-4)
12a-2a+4+6=0
We add all the numbers together, and all the variables
10a+10=0
We move all terms containing a to the left, all other terms to the right
10a=-10
a=-10/10
a=-1
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