3(4a+2)=3(a-2)

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Solution for 3(4a+2)=3(a-2) equation: 



3(4a+2)=3(a-2)

We move all terms to the left:

3(4a+2)-(3(a-2))=0

We multiply parentheses

12a-(3(a-2))+6=0



We calculate terms in parentheses: -(3(a-2)), so:

3(a-2)

We multiply parentheses

3a-6

Back to the equation:

-(3a-6)



We get rid of parentheses

12a-3a+6+6=0

We add all the numbers together, and all the variables

9a+12=0

We move all terms containing a to the left, all other terms to the right

9a=-12

a=-12/9

a=-1+1/3

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