3(4a-2c)-2(2a+4c)=

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Solution for 3(4a-2c)-2(2a+4c)= equation:


Simplifying
3(4a + -2c) + -2(2a + 4c) = 0
(4a * 3 + -2c * 3) + -2(2a + 4c) = 0
(12a + -6c) + -2(2a + 4c) = 0
12a + -6c + (2a * -2 + 4c * -2) = 0
12a + -6c + (-4a + -8c) = 0

Reorder the terms:
12a + -4a + -6c + -8c = 0

Combine like terms: 12a + -4a = 8a
8a + -6c + -8c = 0

Combine like terms: -6c + -8c = -14c
8a + -14c = 0

Solving
8a + -14c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '14c' to each side of the equation.
8a + -14c + 14c = 0 + 14c

Combine like terms: -14c + 14c = 0
8a + 0 = 0 + 14c
8a = 0 + 14c
Remove the zero:
8a = 14c

Divide each side by '8'.
a = 1.75c

Simplifying
a = 1.75c

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