3(4b+1)-2(3b-5)=19

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Solution for 3(4b+1)-2(3b-5)=19 equation: 



3(4b+1)-2(3b-5)=19

We move all terms to the left:

3(4b+1)-2(3b-5)-(19)=0

We multiply parentheses

12b-6b+3+10-19=0

We add all the numbers together, and all the variables

6b-6=0

We move all terms containing b to the left, all other terms to the right

6b=6

b=6/6

b=1

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