3(4b+1)-4(5b+4)=b+59

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Solution for 3(4b+1)-4(5b+4)=b+59 equation: 



3(4b+1)-4(5b+4)=b+59

We move all terms to the left:

3(4b+1)-4(5b+4)-(b+59)=0

We multiply parentheses

12b-20b-(b+59)+3-16=0

We get rid of parentheses

12b-20b-b-59+3-16=0

We add all the numbers together, and all the variables

-9b-72=0

We move all terms containing b to the left, all other terms to the right

-9b=72

b=72/-9

b=-8

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