3(4b+1)-9b=6(2-b)

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Solution for 3(4b+1)-9b=6(2-b) equation: 



3(4b+1)-9b=6(2-b)

We move all terms to the left:

3(4b+1)-9b-(6(2-b))=0

We add all the numbers together, and all the variables

3(4b+1)-9b-(6(-1b+2))=0

We add all the numbers together, and all the variables

-9b+3(4b+1)-(6(-1b+2))=0

We multiply parentheses

-9b+12b-(6(-1b+2))+3=0



We calculate terms in parentheses: -(6(-1b+2)), so:

6(-1b+2)

We multiply parentheses

-6b+12

Back to the equation:

-(-6b+12)



We add all the numbers together, and all the variables

3b-(-6b+12)+3=0

We get rid of parentheses

3b+6b-12+3=0

We add all the numbers together, and all the variables

9b-9=0

We move all terms containing b to the left, all other terms to the right

9b=9

b=9/9

b=1

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