3(4b+1)=51

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Solution for 3(4b+1)=51 equation: 



3(4b+1)=51

We move all terms to the left:

3(4b+1)-(51)=0

We multiply parentheses

12b+3-51=0

We add all the numbers together, and all the variables

12b-48=0

We move all terms containing b to the left, all other terms to the right

12b=48

b=48/12

b=4

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