3(4b-1)=-8(b-4)+5

Solution for 3(4b-1)=-8(b-4)+5 equation:

3(4b-1)=-8(b-4)+5

We move all terms to the left:

3(4b-1)-(-8(b-4)+5)=0

We multiply parentheses

12b-(-8(b-4)+5)-3=0


We calculate terms in parentheses: -(-8(b-4)+5), so:

-8(b-4)+5

We multiply parentheses

-8b+32+5

We add all the numbers together, and all the variables

-8b+37

Back to the equation:

-(-8b+37)


We get rid of parentheses

12b+8b-37-3=0

We add all the numbers together, and all the variables

20b-40=0

We move all terms containing b to the left, all other terms to the right

20b=40

b=40/20

b=2