3(4b-10)=1/2(-24b+60)

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Solution for 3(4b-10)=1/2(-24b+60) equation: 



3(4b-10)=1/2(-24b+60)

We move all terms to the left:

3(4b-10)-(1/2(-24b+60))=0



Domain of the equation: 2(-24b+60))!=0

b∈R



We multiply parentheses

12b-(1/2(-24b+60))-30=0

We multiply all the terms by the denominator


12b*2(-24b+60))-(1-30*2(-24b+60))=0

Wy multiply elements

24b^2(--60b(-=0

We use the square of the difference formula

24b^2(+60b(-=0

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