3(4b-10)=1/2(24b+60)

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Solution for 3(4b-10)=1/2(24b+60) equation: 


b in (-oo:+oo)

3*(4*b-10) = (1/2)*(24*b+60) // - (1/2)*(24*b+60)

3*(4*b-10)-((1/2)*(24*b+60)) = 0

3*(4*b-10)+(-1/2)*(24*b+60) = 0

3*(4*b-10)-1/2*(24*b+60) = 0

3*(4*b-10)-1/2*(24*b+60) = 0

-60 = 0

-60 = 0

b belongs to the empty set

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