3(4b-2)+3=24

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Solution for 3(4b-2)+3=24 equation: 



3(4b-2)+3=24

We move all terms to the left:

3(4b-2)+3-(24)=0

We add all the numbers together, and all the variables

3(4b-2)-21=0

We multiply parentheses

12b-6-21=0

We add all the numbers together, and all the variables

12b-27=0

We move all terms containing b to the left, all other terms to the right

12b=27

b=27/12

b=2+1/4

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