3(4b-2)=2(5b-6)+3b

Solution for 3(4b-2)=2(5b-6)+3b equation:

3(4b-2)=2(5b-6)+3b

We move all terms to the left:

3(4b-2)-(2(5b-6)+3b)=0

We multiply parentheses

12b-(2(5b-6)+3b)-6=0


We calculate terms in parentheses: -(2(5b-6)+3b), so:

2(5b-6)+3b

We add all the numbers together, and all the variables

3b+2(5b-6)

We multiply parentheses

3b+10b-12

We add all the numbers together, and all the variables

13b-12

Back to the equation:

-(13b-12)


We get rid of parentheses

12b-13b+12-6=0

We add all the numbers together, and all the variables

-1b+6=0

We move all terms containing b to the left, all other terms to the right

-b=-6

b=-6/-1

b=+6