3(4b-2)=6=12b

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Solution for 3(4b-2)=6=12b equation: 



3(4b-2)=6=12b

We move all terms to the left:

3(4b-2)-(6)=0

We multiply parentheses

12b-6-6=0

We add all the numbers together, and all the variables

12b-12=0

We move all terms containing b to the left, all other terms to the right

12b=12

b=12/12

b=1

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