3(4b-4)=120

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Solution for 3(4b-4)=120 equation: 



3(4b-4)=120

We move all terms to the left:

3(4b-4)-(120)=0

We multiply parentheses

12b-12-120=0

We add all the numbers together, and all the variables

12b-132=0

We move all terms containing b to the left, all other terms to the right

12b=132

b=132/12

b=11

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