3(4b-5)=-28+12b

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Solution for 3(4b-5)=-28+12b equation:


3(4b-5)=-28+12b

We simplify the equation to the form, which is simple to understand 
3(4b-5)=-28+12b

Reorder the terms in parentheses
+(+12b-15)=-28+12b

Remove unnecessary parentheses
+12b-15=-28+12b

We move all terms containing b to the left and all other terms to the right. 
+12b-12b=-28+15

We simplify left and right side of the equation. 
b=-13

0=-13

The left and right sides are not equal, therefore there is no solution. This equation is invalid.

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