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3(4b-6)=4(3b-7)
We move all terms to the left:
3(4b-6)-(4(3b-7))=0
We multiply parentheses
12b-(4(3b-7))-18=0
We calculate terms in parentheses: -(4(3b-7)), so:We get rid of parentheses
4(3b-7)
We multiply parentheses
12b-28
Back to the equation:
-(12b-28)
12b-12b+28-18=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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