3(4b-6)=7(b+1)

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Solution for 3(4b-6)=7(b+1) equation: 



3(4b-6)=7(b+1)

We move all terms to the left:

3(4b-6)-(7(b+1))=0

We multiply parentheses

12b-(7(b+1))-18=0



We calculate terms in parentheses: -(7(b+1)), so:

7(b+1)

We multiply parentheses

7b+7

Back to the equation:

-(7b+7)



We get rid of parentheses

12b-7b-7-18=0

We add all the numbers together, and all the variables

5b-25=0

We move all terms containing b to the left, all other terms to the right

5b=25

b=25/5

b=5

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