3(4c+1)-17=2(3c+2)-3

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Solution for 3(4c+1)-17=2(3c+2)-3 equation:


Simplifying
3(4c + 1) + -17 = 2(3c + 2) + -3

Reorder the terms:
3(1 + 4c) + -17 = 2(3c + 2) + -3
(1 * 3 + 4c * 3) + -17 = 2(3c + 2) + -3
(3 + 12c) + -17 = 2(3c + 2) + -3

Reorder the terms:
3 + -17 + 12c = 2(3c + 2) + -3

Combine like terms: 3 + -17 = -14
-14 + 12c = 2(3c + 2) + -3

Reorder the terms:
-14 + 12c = 2(2 + 3c) + -3
-14 + 12c = (2 * 2 + 3c * 2) + -3
-14 + 12c = (4 + 6c) + -3

Reorder the terms:
-14 + 12c = 4 + -3 + 6c

Combine like terms: 4 + -3 = 1
-14 + 12c = 1 + 6c

Solving
-14 + 12c = 1 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
-14 + 12c + -6c = 1 + 6c + -6c

Combine like terms: 12c + -6c = 6c
-14 + 6c = 1 + 6c + -6c

Combine like terms: 6c + -6c = 0
-14 + 6c = 1 + 0
-14 + 6c = 1

Add '14' to each side of the equation.
-14 + 14 + 6c = 1 + 14

Combine like terms: -14 + 14 = 0
0 + 6c = 1 + 14
6c = 1 + 14

Combine like terms: 1 + 14 = 15
6c = 15

Divide each side by '6'.
c = 2.5

Simplifying
c = 2.5

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