3(4c+1)=2c+13

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Solution for 3(4c+1)=2c+13 equation:


Simplifying
3(4c + 1) = 2c + 13

Reorder the terms:
3(1 + 4c) = 2c + 13
(1 * 3 + 4c * 3) = 2c + 13
(3 + 12c) = 2c + 13

Reorder the terms:
3 + 12c = 13 + 2c

Solving
3 + 12c = 13 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
3 + 12c + -2c = 13 + 2c + -2c

Combine like terms: 12c + -2c = 10c
3 + 10c = 13 + 2c + -2c

Combine like terms: 2c + -2c = 0
3 + 10c = 13 + 0
3 + 10c = 13

Add '-3' to each side of the equation.
3 + -3 + 10c = 13 + -3

Combine like terms: 3 + -3 = 0
0 + 10c = 13 + -3
10c = 13 + -3

Combine like terms: 13 + -3 = 10
10c = 10

Divide each side by '10'.
c = 1

Simplifying
c = 1

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