3(4c+2)=12c+6

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Solution for 3(4c+2)=12c+6 equation: 



3(4c+2)=12c+6

We move all terms to the left:

3(4c+2)-(12c+6)=0

We multiply parentheses

12c-(12c+6)+6=0

We get rid of parentheses

12c-12c-6+6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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