3(4c+2)=2(c-2)

Solution for 3(4c+2)=2(c-2) equation:

Simplifying
3(4c + 2) = 2(c + -2)

Reorder the terms:
3(2 + 4c) = 2(c + -2)
(2 * 3 + 4c * 3) = 2(c + -2)
(6 + 12c) = 2(c + -2)

Reorder the terms:
6 + 12c = 2(-2 + c)
6 + 12c = (-2 * 2 + c * 2)
6 + 12c = (-4 + 2c)

Solving
6 + 12c = -4 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
6 + 12c + -2c = -4 + 2c + -2c

Combine like terms: 12c + -2c = 10c
6 + 10c = -4 + 2c + -2c

Combine like terms: 2c + -2c = 0
6 + 10c = -4 + 0
6 + 10c = -4

Add '-6' to each side of the equation.
6 + -6 + 10c = -4 + -6

Combine like terms: 6 + -6 = 0
0 + 10c = -4 + -6
10c = -4 + -6

Combine like terms: -4 + -6 = -10
10c = -10

Divide each side by '10'.
c = -1

Simplifying
c = -1