3(4c-10)=6(2c-5)

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Solution for 3(4c-10)=6(2c-5) equation:


Simplifying
3(4c + -10) = 6(2c + -5)

Reorder the terms:
3(-10 + 4c) = 6(2c + -5)
(-10 * 3 + 4c * 3) = 6(2c + -5)
(-30 + 12c) = 6(2c + -5)

Reorder the terms:
-30 + 12c = 6(-5 + 2c)
-30 + 12c = (-5 * 6 + 2c * 6)
-30 + 12c = (-30 + 12c)

Add '30' to each side of the equation.
-30 + 30 + 12c = -30 + 30 + 12c

Combine like terms: -30 + 30 = 0
0 + 12c = -30 + 30 + 12c
12c = -30 + 30 + 12c

Combine like terms: -30 + 30 = 0
12c = 0 + 12c
12c = 12c

Add '-12c' to each side of the equation.
12c + -12c = 12c + -12c

Combine like terms: 12c + -12c = 0
0 = 12c + -12c

Combine like terms: 12c + -12c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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