3(4c-2)-1=10c+5

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Solution for 3(4c-2)-1=10c+5 equation:


Simplifying
3(4c + -2) + -1 = 10c + 5

Reorder the terms:
3(-2 + 4c) + -1 = 10c + 5
(-2 * 3 + 4c * 3) + -1 = 10c + 5
(-6 + 12c) + -1 = 10c + 5

Reorder the terms:
-6 + -1 + 12c = 10c + 5

Combine like terms: -6 + -1 = -7
-7 + 12c = 10c + 5

Reorder the terms:
-7 + 12c = 5 + 10c

Solving
-7 + 12c = 5 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
-7 + 12c + -10c = 5 + 10c + -10c

Combine like terms: 12c + -10c = 2c
-7 + 2c = 5 + 10c + -10c

Combine like terms: 10c + -10c = 0
-7 + 2c = 5 + 0
-7 + 2c = 5

Add '7' to each side of the equation.
-7 + 7 + 2c = 5 + 7

Combine like terms: -7 + 7 = 0
0 + 2c = 5 + 7
2c = 5 + 7

Combine like terms: 5 + 7 = 12
2c = 12

Divide each side by '2'.
c = 6

Simplifying
c = 6

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