3(4c-3)-7=-4(-4c+19)

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Solution for 3(4c-3)-7=-4(-4c+19) equation: 



3(4c-3)-7=-4(-4c+19)

We move all terms to the left:

3(4c-3)-7-(-4(-4c+19))=0

We multiply parentheses

12c-(-4(-4c+19))-9-7=0



We calculate terms in parentheses: -(-4(-4c+19)), so:

-4(-4c+19)

We multiply parentheses

16c-76

Back to the equation:

-(16c-76)



We add all the numbers together, and all the variables

12c-(16c-76)-16=0

We get rid of parentheses

12c-16c+76-16=0

We add all the numbers together, and all the variables

-4c+60=0

We move all terms containing c to the left, all other terms to the right

-4c=-60

c=-60/-4

c=+15

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