3(4c-3)=2(c+8)

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Solution for 3(4c-3)=2(c+8) equation: 



3(4c-3)=2(c+8)

We move all terms to the left:

3(4c-3)-(2(c+8))=0

We multiply parentheses

12c-(2(c+8))-9=0



We calculate terms in parentheses: -(2(c+8)), so:

2(c+8)

We multiply parentheses

2c+16

Back to the equation:

-(2c+16)



We get rid of parentheses

12c-2c-16-9=0

We add all the numbers together, and all the variables

10c-25=0

We move all terms containing c to the left, all other terms to the right

10c=25

c=25/10

c=2+1/2

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