3(4c-5)+3=35

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Solution for 3(4c-5)+3=35 equation: 



3(4c-5)+3=35

We move all terms to the left:

3(4c-5)+3-(35)=0

We add all the numbers together, and all the variables

3(4c-5)-32=0

We multiply parentheses

12c-15-32=0

We add all the numbers together, and all the variables

12c-47=0

We move all terms containing c to the left, all other terms to the right

12c=47

c=47/12

c=3+11/12

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