3(4c-6)-9c=8c+17

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Solution for 3(4c-6)-9c=8c+17 equation: 



3(4c-6)-9c=8c+17

We move all terms to the left:

3(4c-6)-9c-(8c+17)=0

We add all the numbers together, and all the variables

-9c+3(4c-6)-(8c+17)=0

We multiply parentheses

-9c+12c-(8c+17)-18=0

We get rid of parentheses

-9c+12c-8c-17-18=0

We add all the numbers together, and all the variables

-5c-35=0

We move all terms containing c to the left, all other terms to the right

-5c=35

c=35/-5

c=-7

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