3(4c-7)=2(3c+11)+5

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Solution for 3(4c-7)=2(3c+11)+5 equation:


Simplifying
3(4c + -7) = 2(3c + 11) + 5

Reorder the terms:
3(-7 + 4c) = 2(3c + 11) + 5
(-7 * 3 + 4c * 3) = 2(3c + 11) + 5
(-21 + 12c) = 2(3c + 11) + 5

Reorder the terms:
-21 + 12c = 2(11 + 3c) + 5
-21 + 12c = (11 * 2 + 3c * 2) + 5
-21 + 12c = (22 + 6c) + 5

Reorder the terms:
-21 + 12c = 22 + 5 + 6c

Combine like terms: 22 + 5 = 27
-21 + 12c = 27 + 6c

Solving
-21 + 12c = 27 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
-21 + 12c + -6c = 27 + 6c + -6c

Combine like terms: 12c + -6c = 6c
-21 + 6c = 27 + 6c + -6c

Combine like terms: 6c + -6c = 0
-21 + 6c = 27 + 0
-21 + 6c = 27

Add '21' to each side of the equation.
-21 + 21 + 6c = 27 + 21

Combine like terms: -21 + 21 = 0
0 + 6c = 27 + 21
6c = 27 + 21

Combine like terms: 27 + 21 = 48
6c = 48

Divide each side by '6'.
c = 8

Simplifying
c = 8

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