3(4c-7)=4(c-1)

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Solution for 3(4c-7)=4(c-1) equation: 



3(4c-7)=4(c-1)

We move all terms to the left:

3(4c-7)-(4(c-1))=0

We multiply parentheses

12c-(4(c-1))-21=0



We calculate terms in parentheses: -(4(c-1)), so:

4(c-1)

We multiply parentheses

4c-4

Back to the equation:

-(4c-4)



We get rid of parentheses

12c-4c+4-21=0

We add all the numbers together, and all the variables

8c-17=0

We move all terms containing c to the left, all other terms to the right

8c=17

c=17/8

c=2+1/8

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