3(4c-9)=5(2c-5)

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Solution for 3(4c-9)=5(2c-5) equation:


Simplifying
3(4c + -9) = 5(2c + -5)

Reorder the terms:
3(-9 + 4c) = 5(2c + -5)
(-9 * 3 + 4c * 3) = 5(2c + -5)
(-27 + 12c) = 5(2c + -5)

Reorder the terms:
-27 + 12c = 5(-5 + 2c)
-27 + 12c = (-5 * 5 + 2c * 5)
-27 + 12c = (-25 + 10c)

Solving
-27 + 12c = -25 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
-27 + 12c + -10c = -25 + 10c + -10c

Combine like terms: 12c + -10c = 2c
-27 + 2c = -25 + 10c + -10c

Combine like terms: 10c + -10c = 0
-27 + 2c = -25 + 0
-27 + 2c = -25

Add '27' to each side of the equation.
-27 + 27 + 2c = -25 + 27

Combine like terms: -27 + 27 = 0
0 + 2c = -25 + 27
2c = -25 + 27

Combine like terms: -25 + 27 = 2
2c = 2

Divide each side by '2'.
c = 1

Simplifying
c = 1

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