3(4d+1)+9d=6(2-d)

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Solution for 3(4d+1)+9d=6(2-d) equation: 



3(4d+1)+9d=6(2-d)

We move all terms to the left:

3(4d+1)+9d-(6(2-d))=0

We add all the numbers together, and all the variables

3(4d+1)+9d-(6(-1d+2))=0

We add all the numbers together, and all the variables

9d+3(4d+1)-(6(-1d+2))=0

We multiply parentheses

9d+12d-(6(-1d+2))+3=0



We calculate terms in parentheses: -(6(-1d+2)), so:

6(-1d+2)

We multiply parentheses

-6d+12

Back to the equation:

-(-6d+12)



We add all the numbers together, and all the variables

21d-(-6d+12)+3=0

We get rid of parentheses

21d+6d-12+3=0

We add all the numbers together, and all the variables

27d-9=0

We move all terms containing d to the left, all other terms to the right

27d=9

d=9/27

d=1/3

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