3(4d+1)-4d=6(2-d)

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Solution for 3(4d+1)-4d=6(2-d) equation:



3(4d+1)-4d=6(2-d)
We move all terms to the left:
3(4d+1)-4d-(6(2-d))=0
We add all the numbers together, and all the variables
3(4d+1)-4d-(6(-1d+2))=0
We add all the numbers together, and all the variables
-4d+3(4d+1)-(6(-1d+2))=0
We multiply parentheses
-4d+12d-(6(-1d+2))+3=0
We calculate terms in parentheses: -(6(-1d+2)), so:
6(-1d+2)
We multiply parentheses
-6d+12
Back to the equation:
-(-6d+12)
We add all the numbers together, and all the variables
8d-(-6d+12)+3=0
We get rid of parentheses
8d+6d-12+3=0
We add all the numbers together, and all the variables
14d-9=0
We move all terms containing d to the left, all other terms to the right
14d=9
d=9/14
d=9/14

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