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3(4d+1)-9d=6(2+d
We move all terms to the left:
3(4d+1)-9d-(6(2+d)=0
We add all the numbers together, and all the variables
3(4d+1)-9d-(6(d+2)=0
We add all the numbers together, and all the variables
-9d+3(4d+1)-(6(d+2)=0
We multiply parentheses
-9d+12d-(6(d+2)+3=0
We add all the numbers together, and all the variables
3d-(6(d+2)+3=0
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