3(4f+-1)f=2.

Solution for 3(4f+-1)f=2. equation:

3(4f+-1)f=2.

We move all terms to the left:

3(4f+-1)f-(2.)=0

We add all the numbers together, and all the variables

3(4f-1)f-2=0

We multiply parentheses

12f^2-3f-2=0

a = 12; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·12·(-2)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*12}=\frac{3-\sqrt{105}}{24}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*12}=\frac{3+\sqrt{105}}{24}
$