3(4f-10)-15=2(2f+15)+13

Solution for 3(4f-10)-15=2(2f+15)+13 equation:

3(4f-10)-15=2(2f+15)+13

We move all terms to the left:

3(4f-10)-15-(2(2f+15)+13)=0

We multiply parentheses

12f-(2(2f+15)+13)-30-15=0


We calculate terms in parentheses: -(2(2f+15)+13), so:

2(2f+15)+13

We multiply parentheses

4f+30+13

We add all the numbers together, and all the variables

4f+43

Back to the equation:

-(4f+43)


We add all the numbers together, and all the variables

12f-(4f+43)-45=0

We get rid of parentheses

12f-4f-43-45=0

We add all the numbers together, and all the variables

8f-88=0

We move all terms containing f to the left, all other terms to the right

8f=88

f=88/8

f=11