3(4f-2)=2(4f+1)

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Solution for 3(4f-2)=2(4f+1) equation: 



3(4f-2)=2(4f+1)

We move all terms to the left:

3(4f-2)-(2(4f+1))=0

We multiply parentheses

12f-(2(4f+1))-6=0



We calculate terms in parentheses: -(2(4f+1)), so:

2(4f+1)

We multiply parentheses

8f+2

Back to the equation:

-(8f+2)



We get rid of parentheses

12f-8f-2-6=0

We add all the numbers together, and all the variables

4f-8=0

We move all terms containing f to the left, all other terms to the right

4f=8

f=8/4

f=2

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