3(4f-20)=18-6(9f-20)

Solution for 3(4f-20)=18-6(9f-20) equation:

3(4f-20)=18-6(9f-20)

We move all terms to the left:

3(4f-20)-(18-6(9f-20))=0

We multiply parentheses

12f-(18-6(9f-20))-60=0


We calculate terms in parentheses: -(18-6(9f-20)), so:

18-6(9f-20)

determiningTheFunctionDomain
-6(9f-20)+18

We multiply parentheses

-54f+120+18

We add all the numbers together, and all the variables

-54f+138

Back to the equation:

-(-54f+138)


We get rid of parentheses

12f+54f-138-60=0

We add all the numbers together, and all the variables

66f-198=0

We move all terms containing f to the left, all other terms to the right

66f=198

f=198/66

f=3