3(4j+1)=9j-3(3j-1)+j

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Solution for 3(4j+1)=9j-3(3j-1)+j equation: 



3(4j+1)=9j-3(3j-1)+j

We move all terms to the left:

3(4j+1)-(9j-3(3j-1)+j)=0

We multiply parentheses

12j-(9j-3(3j-1)+j)+3=0



We calculate terms in parentheses: -(9j-3(3j-1)+j), so:

9j-3(3j-1)+j

We add all the numbers together, and all the variables

10j-3(3j-1)

We multiply parentheses

10j-9j+3

We add all the numbers together, and all the variables

j+3

Back to the equation:

-(j+3)



We get rid of parentheses

12j-j-3+3=0

We add all the numbers together, and all the variables

11j=0

j=0/11

j=0

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