3(4j+10)=150

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Solution for 3(4j+10)=150 equation: 



3(4j+10)=150

We move all terms to the left:

3(4j+10)-(150)=0

We multiply parentheses

12j+30-150=0

We add all the numbers together, and all the variables

12j-120=0

We move all terms containing j to the left, all other terms to the right

12j=120

j=120/12

j=10

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