3(4j-5)=4j+7j+4-3

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Solution for 3(4j-5)=4j+7j+4-3 equation: 



3(4j-5)=4j+7j+4-3

We move all terms to the left:

3(4j-5)-(4j+7j+4-3)=0

We add all the numbers together, and all the variables

3(4j-5)-(11j+1)=0

We multiply parentheses

12j-(11j+1)-15=0

We get rid of parentheses

12j-11j-1-15=0

We add all the numbers together, and all the variables

j-16=0

We move all terms containing j to the left, all other terms to the right

j=16

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