3(4k+10)=10+2(k+5)

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Solution for 3(4k+10)=10+2(k+5) equation: 



3(4k+10)=10+2(k+5)

We move all terms to the left:

3(4k+10)-(10+2(k+5))=0

We multiply parentheses

12k-(10+2(k+5))+30=0



We calculate terms in parentheses: -(10+2(k+5)), so:

10+2(k+5)

determiningTheFunctionDomain
2(k+5)+10

We multiply parentheses

2k+10+10

We add all the numbers together, and all the variables

2k+20

Back to the equation:

-(2k+20)



We get rid of parentheses

12k-2k-20+30=0

We add all the numbers together, and all the variables

10k+10=0

We move all terms containing k to the left, all other terms to the right

10k=-10

k=-10/10

k=-1

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