3(4k-2)+15=12k+9

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Solution for 3(4k-2)+15=12k+9 equation: 



3(4k-2)+15=12k+9

We move all terms to the left:

3(4k-2)+15-(12k+9)=0

We multiply parentheses

12k-(12k+9)-6+15=0

We get rid of parentheses

12k-12k-9-6+15=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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